John Roseboro: Facts & Related Content
John Roseboro is a MLB baseball player. He was born on May 13, 1933
Facts
| Birthplace | Ashland, Ohio, United States |
|---|---|
| Birth Date | May 13, 1933 |
| Place Of Death | Los Angeles, California, United States |
| Date Of Death | August 16, 2002 |
| Height/Weight | 5 ft 11 inches, 190 lb (180 cm, 86 kg) |
| Batting Hand | left |
| Throwing Hand | right |
| Debut Date | June 14, 1957 |
| Last Game | August 11, 1970 |
| Jersey Number | 13 (1970-1970, Washington Senators) • 13 (1968-1969, Minnesota Twins) • 10 (1968-1968, Minnesota Twins) • 44 (1959-1960, Los Angeles Dodgers) • 8 (1958-1967, Los Angeles Dodgers) • 8 (1957-1957, Brooklyn Dodgers) |
| Position | catcher |
| At Bats | 4,847 |
| Batting Average | 0.249 |
| Hits | 1,206 |
| Home Runs | 104 |
| On-Base Percentage | 0.326 |
| On-Base Plus Slugging | 0.697 |
| Runs | 512 |
| Runs Batted In | 548 |
| Slugging Percentage | 0.371 |
| Stolen Bases | 67 |
Top Questions
What was John Roseboro's batting average?
John Roseboro had a career batting average of 0.249.
How many home runs did John Roseboro hit?
John Roseboro hit 104 home runs during his career.
How many hits did John Roseboro have?
John Roseboro had 1,206 hits in his career.
How tall was John Roseboro?
John Roseboro was 5 ft 11 inches, 190 lb (180 cm, 86 kg).
When was John Roseboro born?
John Roseboro was born on May 13, 1933.
What position did John Roseboro play?
John Roseboro played catcher.
Where was John Roseboro born?
John Roseboro was born in Ashland, Ohio, United States.